用書:Physics for scientists and engineers(with modern physics)(ninth edition)
作者:Raymond A. Serway/ John W. Jewett
參考書籍/作者:大學物理/Zill Y. Chen
筆記作者:曾理碩/啾咪喵
分享模式:創用 cc 姓名標示-相同方式分享
(cc 分享限筆記、作業解答,不包括連外文件、作業)
部格相關連結:
[總單]課程總單
[物理]總單
[總單]課程總單
[物理]總單
前言:
因為是筆記,通常以自己不會的地方做加強
主要寫概念
而較多複雜邏輯推理的地方會略過
因此使用時請作為導引手冊
請務必搭配課本使用(上方有連結)
==========(以下為筆記內容,因為格式關係,完整資料請下載PDF)==========
= -
(volt)
(單位時間內磁通量變化)
= -
(BAcos
)
= -
(BAcos
)
= -
(BAcos
)
= -
dt
= vB
= vBdr
= r
Bdr
= - 
= BAcos
= BAcos(
t)
= -N
= NAB
sin(
t)
= 
31.1 基礎公式
磁通量對時間場生變化就會產生感應電動式
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題目若要計算I,先算
,再代公式
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I =
(R = 電阻,
可視為電壓)
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31.2 動生電動式(Momentional
emf)
計算
& I
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B改變
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面積改變時通常為圈數變化,*N圈即可
B不改變,A改變
平行軌道拉導線且與磁場垂直、一線圈拉入均勻垂直磁場
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= - Bcos0
A (單位時間面積變化就是軌道間距*拉導線速度
A = Lv)

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= - BLv
計算施力
將一線圈拉入均勻垂直磁場中
F = I
x
(CH29長直電線受垂直磁力,在線圈其中一邊上產生)
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=
NLB =
NLB =
NLB (N為線圈圈數)
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= 
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計算功率P(power) = 單位時間做功
感應電路上電阻器消耗功率
P =
R =
= 
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平行軌道上,外力提供功率
P = Fv = ILBv =
= 
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計算
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P
= Fv = 
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31.3 冷次定律
線路抵抗磁場變化而產生電流
殘檔案:
F = ma = m
= -ILB

m
= -
v
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qE = qvB
E = vB
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法拉第微分表示式
法拉第積分表示式
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E2
r = ,…
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旋轉
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EdA =
q/
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BdA = 0
Eds = -
Faraday’s Law
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Eds =
34.2
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E =
cos(kx-
)
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B =
cos(kx-
)
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2
= kλ = 
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v = 
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